# Motion with Uniform Acceleration - Example 6

Example 6
A car begins to move from rest. The velocity of the car increases at a rate of 4 ms-2. Find the distance traveled by the car after 12 second.

It's advisable to list down all the information that we have.

Initial velocity, u = 0 (Because the begins to move from rest)
Acceleration, a = 4 ms-2 (Rate of increment = Acceleration)
Time taken, t = 12s
Displacement, s = ?

The final velocity, v, is not involved, hence we select the equation $$s = ut + \frac{1}{2}a{t^2}$$ to solve the problem. $s=ut+ 1 2 a t 2 s=(0)(12)+ 1 2 (4) (12) 2 s=288m$

### Reference

$v=u+at s=ut+ 1 2 a t 2 v 2 = u 2 +2as s= 1 2 (u+v)t$