Motion with Uniform Acceleration - Example 4

Example 4
A car is accelerated at 4 ms^-2 from an initial velocity of 5 ms^-1 for 10 seconds. What is the distance traveled by the car?

Answer:
It's advisable to list down all the information that we have.

Acceleration, a = 4 ms^-2
Initial velocity, u = 5
Time taken, t = 10s
Displacement, s = ?

The final velocity, v, is not involved, hence we select the equation \(s = ut + \frac{1}{2}a{t^2}\) to solve the problem. $$\begin{array}{l}s=ut+\frac{1}{2}a{t}^2\\ s=(5)(10)+\frac{1}{2}(4){\left(10\right)}^2\\ s=50+200=250m\end{array}$$

Reference

$$\begin{array}{l}v=u+at\\ s=ut+\frac{1}{2}a{t}^2\\ v^2=u^2+2as\\ s=\frac{1}{2}(u+v)t\end{array}$$

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Uniform Acceleration - Example 4