Example 1:
Figure above shows 3 identical capillary tubes with one end sealed and containing a column of mercury. PA, PB and PC are the gas pressure in the capillary tubes respectively. Find the value of PA, PB and PC. [Atmospheric pressure = 76cmHg]
Answer:
PA = 76cmHg
PB = 76cmHg + 2cmHg = 78cmHg
PC = 76cmHg - 2cmHg = 74cmHg
Figure above shows 3 identical capillary tubes with one end sealed and containing a column of mercury. PA, PB and PC are the gas pressure in the capillary tubes respectively. Find the value of PA, PB and PC. [Atmospheric pressure = 76cmHg]
Answer:
PA = 76cmHg
PB = 76cmHg + 2cmHg = 78cmHg
PC = 76cmHg - 2cmHg = 74cmHg
