# Finding Resistance of an Individual Resistor

Finding the Resistance of an Individual Resistor

Example 1

Given that the equivalent resistance of the connection in the figure above is 0.8Ω, find the resistance of the resistor R.

$R= ( 1 2 + 1 R + 1 4 ) −1 =0.8 ( 1 2 + 1 R + 1 4 )= 0.8 −1 = 5 4 1 R = 5 4 − 1 2 − 1 4 = 1 2 R=2Ω$
$( 1 2+R + 1 3 ) −1 +2=4 ( 1 2+R + 1 3 ) −1 =4−2=2 ( 1 2+R + 1 3 )= 2 −1 1 2+R = 1 2 − 1 3 1 2+R = 1 6 2+R=6 R=4Ω$