Motion with Uniform Acceleration - Example 2

Example 2
A car is moving with velocity 5ms-1 reaches a velocity of 25ms-1 in 5s. What is the acceleration of the car?

Answer:
It's advisable to list down all the information that we have.

Initial velocity, u = 5ms-1
Final velocity, v = 25ms-1
Time taken, t = 5s
Acceleration, a = ?

The displacement, s, is not involved, hence we select the equation \(v = u + at\) to solve the problem. v=u+at (25)=(5)+a(5) 5a=255 a= 255 5 =4m s 2


Reference

v=u+at s=ut+ 1 2 a t 2 v 2 = u 2 +2as s= 1 2 (u+v)t


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Uniform Acceleration - Example 2