Motion with Uniform Acceleration - Example 2

Example 2
A car is moving with velocity 5ms^-1 reaches a velocity of 25ms^-1 in 5s. What is the acceleration of the car?

Answer:
It's advisable to list down all the information that we have.

Initial velocity, u = 5ms^-1
Final velocity, v = 25ms^-1
Time taken, t = 5s
Acceleration, a = ?

The displacement, s, is not involved, hence we select the equation \(v = u + at\) to solve the problem. $$\begin{array}{l}v=u+at\\ (25)=(5)+a(5)\\ 5a=25-5\\ a=\frac{25-5}{5}=4m{s}^{-2}\end{array}$$

Reference

$$\begin{array}{l}v=u+at\\ s=ut+\frac{1}{2}a{t}^2\\ v^2=u^2+2as\\ s=\frac{1}{2}(u+v)t\end{array}$$

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Uniform Acceleration - Example 2